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Results & Lemmas (8)

Each result is auto-extracted from the paper via OCR - the math is shown verbatim and may carry occasional transcription artifacts. Click to expand the full statement.

Theorem 1. Theorem 1. Let the function f(z) be defined by (1.1). Also let the following in- equality holds true: ∞ ∑ k=2  (k −1)+|ζ(1+m)+m(k −1)|
Theorem 1. Let the function f(z) be defined by (1.1). Also let the following in- equality holds true: ∞ ∑ k=2  (k −1)+|ζ(1+m)+m(k −1)|
Corollary 1. Corollary 1. Let the function f(z) be defined by (1.1). Also let the following inequality holds true: ∞ ∑ k=2 (k −1)+|ζ(1+m)+m(k −1)| |ak|·…
Corollary 1. Let the function f(z) be defined by (1.1). Also let the following inequality holds true: ∞ ∑ k=2 {(k −1)+|ζ(1+m)+m(k −1)|}|ak|· k! (λ+1)k−1 m+1 m+k α ≦|ζ(1+m)|. (2.2) Then the function f(z) belongs to the class S λ,α m (ζ,M ).
Corollary 2. Corollary 2. Let the function f(z) be defined by (1.1). Also let the following inequality holds true: ∞ ∑ k=2 (k −1)+|ζ(1+m)+m(k −1)| |ak|…
Corollary 2. Let the function f(z) be defined by (1.1). Also let the following inequality holds true: ∞ ∑ k=2 {(k −1)+|ζ(1+m)+m(k −1)|}|ak| [k]q! [λ+1]q,k−1 ≦|ζ(1+m)|. (2.3) Then the function f(z) belongs to the class F λ q (ζ,M ).
Theorem 2. Theorem 2. Let the function f(z) given by (1.1) be in the normalized complex- order analytic function class H λ,α m,q (ζ,M ). (a) If 2m(k…
Theorem 2. Let the function f(z) given by (1.1) be in the normalized complex- order analytic function class H λ,α m,q (ζ,M ). (a) If 2m(k −1)ℜ(ζ) > (k −1)2(1−m)−|ζ|2 (1+m), let G = " 2m(k −1)ℜ(ζ) (k −1)2(1−m)−|ζ|2 (1+m) # (k = 2,3,4,··· , j −1), where N = [G] (the Gaussian symbol) and [G] is the greatest integer not greater than G. Then aj
Corollary 3. Corollary 3. Let the function f(z) defined by (1.1) be in the class S λ,α m (ζ,M ). (a) If 2m(k −1)ℜ(ζ) > (k −1)2(1−m)−|ζ|2 (1+m), let G = "…
Corollary 3. Let the function f(z) defined by (1.1) be in the class S λ,α m (ζ,M ). (a) If 2m(k −1)ℜ(ζ) > (k −1)2(1−m)−|ζ|2 (1+m), let G = " 2m(k −1)ℜ(ζ) (k −1)2(1−m)−|ζ|2 (1+m) # (k = 2,3,4,··· , j −1), where N = [G](the Gaussian symbol) and [G] is the greatest integer not greater than G. Then aj ≦
Corollary 4. Corollary 4. Let the function f(z) be defined by (1.1) be in the class F λ q (ζ,M ). (a) If 2m(k −1)ℜ(ζ) > (k −1)2(1−m)−|ζ|2 (1+m), let G =…
Corollary 4. Let the function f(z) be defined by (1.1) be in the class F λ q (ζ,M ). (a) If 2m(k −1)ℜ(ζ) > (k −1)2(1−m)−|ζ|2 (1+m), let G = " 2m(k −1)ℜ(ζ) (k −1)2(1−m)−|ζ|2 (1+m) # (k = 2,3,4,··· , j −1), where N = [G](the Gaussian symbol) and [G] is the greatest integer not greater than G. Then aj ≦
Lemma 1 Lemma 1 ([10]). Let w(z) = ∞ ∑ k=1 ckzk ∈Ω. If µ is any complex number, then c2 −µc2 1 ≦max 1,|µ| (4.1) for any complex number µ. Equality…
Lemma 1 ([10]). Let w(z) = ∞ ∑ k=1 ckzk ∈Ω. If µ is any complex number, then c2 −µc2 1 ≦max{1,|µ|} (4.1) for any complex number µ. Equality in (4.1) may be attained with the functions w(z) = z2 and w(z) = z for |µ| < 1 and |µ| ≧1, respectively. We now state and prove our main result in this section.
Theorem 3. Theorem 3. Let the function f(z) defined by (1.1) be in the normalized complex- order analytic function class H λ,α m,q (ζ,M ). Suppose also…
Theorem 3. Let the function f(z) defined by (1.1) be in the normalized complex- order analytic function class H λ,α m,q (ζ,M ). Suppose also that µ is any complex num- ber. Then a3 −µa2 2 ≦ |ζ(1+m)| 2 [3]q! [λ+1]q,2 m+1 m+3 α max{1,|δ|}, (4.2)
Function classes studied:

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