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Ma-Minda φ-classes studied in this paper:
Abstract

This paper is concerned with the upper bound of various coefficient functionals for a certain subclass of analytic functions associated with exponential function in the open unit disc E = {z ∈C : |z| < 1}. This investigation will motivate other researchers to work in this direction. Mathematics Subject Classification 2010: 30C45, 30C50

Results & Lemmas (24)

Each result is auto-extracted from the paper via OCR - the math is shown verbatim and may carry occasional transcription artifacts. Click to expand the full statement.

LEMMA 1. LEMMA 1. [24; 11] If p ∈P, then |pk| ≤2,k ∈N, p2 − p2 1 2 ≤2−|p1|2 2, |pi+j −µ pip j| ≤2,0 ≤µ ≤1, |pn+2k −λ pnp2 k| ≤2(1+2λ),(λ ∈R), |pmpn…
LEMMA 1. [24; 11] If p ∈P, then |pk| ≤2,k ∈N, p2 − p2 1 2 ≤2−|p1|2 2 , |pi+j −µ pip j| ≤2,0 ≤µ ≤1, |pn+2k −λ pnp2 k| ≤2(1+2λ),(λ ∈R), |pmpn −pkpl| ≤4,(m+n = k +l;m,n ∈N), and for complex number ρ, we have |p2 −ρ p2 1| ≤2max{1,|2ρ −1|}.
LEMMA 2. LEMMA 2. Let p ∈P, then |Jp3 1 −Kp1p2 +Lp3| ≤2|J|+2|K −2J|+2|J −K +L|. In particular, it is proved in [24] that |p3 1 −2p1p2 + p3| ≤2.
LEMMA 2. Let p ∈P, then |Jp3 1 −Kp1p2 +Lp3| ≤2|J|+2|K −2J|+2|J −K +L|. In particular, it is proved in [24] that |p3 1 −2p1p2 + p3| ≤2.
LEMMA 3. · coeff LEMMA 3. [14; 15] If p ∈P, then 2p2 = p2 1 +(4−p2 1)x, 4p3 = p3 1 +2p1(4−p2 1)x−p1(4−p2 1)x2 +2(4−p2 1)(1−|x|2)z, for |x| ≤1 and |z| ≤1. 2.…
LEMMA 3. [14; 15] If p ∈P, then 2p2 = p2 1 +(4−p2 1)x, 4p3 = p3 1 +2p1(4−p2 1)x−p1(4−p2 1)x2 +2(4−p2 1)(1−|x|2)z, for |x| ≤1 and |z| ≤1. 2. COEFFICIENT INEQUALITIES
THEOREM 1. THEOREM 1. If f ∈Rα(ez), then |a2| ≤ 1 1+α, (2) |a3| ≤ 1 1+2α, (3) |a4| ≤ 1 1+3α, (4) and |a5| ≤
THEOREM 1. If f ∈Rα(ez), then |a2| ≤ 1 1+α , (2) |a3| ≤ 1 1+2α , (3) |a4| ≤ 1 1+3α , (4) and |a5| ≤
COROLLARY 1. COROLLARY 1. If f ∈R ′(ez), then |a2| ≤1,|a3| ≤1,|a4| ≤1,|a5| ≤37 24. For α = 1, Theorem 1 gives the following result due to Kumar and…
COROLLARY 1. If f ∈R ′(ez), then |a2| ≤1,|a3| ≤1,|a4| ≤1,|a5| ≤37 24. For α = 1, Theorem 1 gives the following result due to Kumar and Sharma [12]:
COROLLARY 2. COROLLARY 2. If f ∈R(ez), then |a2| ≤1 2,|a3| ≤1 3,|a4| ≤1 4,|a5| ≤37 120.
COROLLARY 2. If f ∈R(ez), then |a2| ≤1 2,|a3| ≤1 3,|a4| ≤1 4,|a5| ≤37 120.
THEOREM 2. THEOREM 2. If f ∈Rα(ez), then |a3 −a2 2| ≤ 1 1+2α. (17) PROOF. From (10) and (11), we have |a3 −a2 2| = 1 2(1+2α) p2 −α2 +6α +3 4(1+α)2 p2…
THEOREM 2. If f ∈Rα(ez), then |a3 −a2 2| ≤ 1 1+2α . (17) PROOF. From (10) and (11), we have |a3 −a2 2| = 1 2(1+2α) p2 −α2 +6α +3 4(1+α)2 p2 1 .
COROLLARY 3. COROLLARY 3. If f ∈R ′(ez), then |a3 −a2 2| ≤1. Putting α = 1, Theorem 2 yields the following result due to Kumar and Sharma [12]:
COROLLARY 3. If f ∈R ′(ez), then |a3 −a2 2| ≤1. Putting α = 1, Theorem 2 yields the following result due to Kumar and Sharma [12]:
COROLLARY 4. COROLLARY 4. If f ∈R(ez), then
COROLLARY 4. If f ∈R(ez), then
THEOREM 3. THEOREM 3. If f ∈Rα(ez), then |a2a3 −a4| ≤ 1 1+3α. (20) PROOF. Using (10), (11), (12) and after simplification, we have |a2a3 −a4| = 1…
THEOREM 3. If f ∈Rα(ez), then |a2a3 −a4| ≤ 1 1+3α . (20) PROOF. Using (10), (11), (12) and after simplification, we have |a2a3 −a4| = 1 48(1+α)(1+2α)(1+3α) (4+12α +2α2)p3 1− (24+72α +24α2)p1p2 +24(1+α)(1+2α)p3 . (21) On applying Lemma 2 in (21), it yields (20).
COROLLARY 5. COROLLARY 5. If f ∈R ′(ez), then |a2a3 −a4| ≤1. On putting α = 1 in Theorem 3, we can obtain the following result due to Kumar and Sharma…
COROLLARY 5. If f ∈R ′(ez), then |a2a3 −a4| ≤1. On putting α = 1 in Theorem 3, we can obtain the following result due to Kumar and Sharma [12]:
COROLLARY 6. COROLLARY 6. If f ∈R(ez), then |a2a3 −a4| ≤1 4.
COROLLARY 6. If f ∈R(ez), then |a2a3 −a4| ≤1 4.
THEOREM 4. THEOREM 4. If f ∈Rα(ez), then |a2a4 −a2 3| ≤ 1 (1+2α)2. (22) The bound is sharp. PROOF. Using (10), (11) and (12), we have |a2a4 −a2 3| = 1…
THEOREM 4. If f ∈Rα(ez), then |a2a4 −a2 3| ≤ 1 (1+2α)2 . (22) The bound is sharp. PROOF. Using (10), (11) and (12), we have |a2a4 −a2 3| = 1 192(1+α)(1+2α)2(1+3α) 48(1+2α)2p1p3 −24α2p2 1p2+ (−1−4α −α2)p4
COROLLARY 7. COROLLARY 7. If f ∈R ′(ez), then |a2a4 −a2 3| ≤1. Substituting for α = 1 in Theorem 4, the following result due to Kumar and Sharma [12],…
COROLLARY 7. If f ∈R ′(ez), then |a2a4 −a2 3| ≤1. Substituting for α = 1 in Theorem 4, the following result due to Kumar and Sharma [12], is obvious:
COROLLARY 8. COROLLARY 8. If f ∈R(ez), then |a2a4 −a2 3| ≤1 9.
COROLLARY 8. If f ∈R(ez), then |a2a4 −a2 3| ≤1 9.
THEOREM 5. THEOREM 5. If f ∈Rα(ez), then |H3(1)| ≤85+850α +3025α2 +4428α3 +2100α4) 24(1+2α)3(1+3α)2(1+4α). (23)
THEOREM 5. If f ∈Rα(ez), then |H3(1)| ≤85+850α +3025α2 +4428α3 +2100α4) 24(1+2α)3(1+3α)2(1+4α) . (23)
COROLLARY 9. COROLLARY 9. If f ∈R ′(ez), then |H3(1)| ≤85 24. For α = 1, Theorem 5 yields the following result:
COROLLARY 9. If f ∈R ′(ez), then |H3(1)| ≤85 24. For α = 1, Theorem 5 yields the following result:
COROLLARY 10. COROLLARY 10. If f ∈R(ez), then |H3(1)| ≤437 2160. 3. BOUNDS OF |H3(1)| FOR TWO-FOLD AND THREE-FOLD SYMMETRIC FUNCTIONS A function f is…
COROLLARY 10. If f ∈R(ez), then |H3(1)| ≤437 2160. 3. BOUNDS OF |H3(1)| FOR TWO-FOLD AND THREE-FOLD SYMMETRIC FUNCTIONS A function f is said to be n-fold symmetric if is satisfy the following condition: f(ξz) = ξ f(z) where ξ = e 2πi n and z ∈E. By S(n), we denote the set of all n-fold symmetric functions which belong to the class S. The n-fold univalent function have the following Taylor-Maclaurin series: f(z) = z+
THEOREM 6. THEOREM 6. If f ∈Rα(2)(ez), then |H3(1)| ≤ 1 (1+2α)(1+4α). (26)
THEOREM 6. If f ∈Rα(2)(ez), then |H3(1)| ≤ 1 (1+2α)(1+4α). (26)
COROLLARY 11. COROLLARY 11. If f ∈R ′(2)(ez), then |H3(1)| ≤1. For α = 1, Theorem 6 agrees with the following result:
COROLLARY 11. If f ∈R ′(2)(ez), then |H3(1)| ≤1. For α = 1, Theorem 6 agrees with the following result:
COROLLARY 12. COROLLARY 12. If f ∈R(2)(ez), then |H3(1)| ≤1 15.
COROLLARY 12. If f ∈R(2)(ez), then |H3(1)| ≤1 15.
THEOREM 7. THEOREM 7. If f ∈Rα(3)(ez), then |H3(1)| ≤ 1 (1+3α)2. (32) PROOF. If f ∈Rα(3)(ez), so there exists a function p ∈P(3) such that (1−α) f(z)…
THEOREM 7. If f ∈Rα(3)(ez), then |H3(1)| ≤ 1 (1+3α)2 . (32) PROOF. If f ∈Rα(3)(ez), so there exists a function p ∈P(3) such that (1−α) f(z) z +α f ′(z) = e  p(z)−1 p(z)+1  . (33)
COROLLARY 13. COROLLARY 13. If f ∈R ′(3)(ez), then |H3(1)| ≤1. For α = 1, Theorem 7 yields the following result:
COROLLARY 13. If f ∈R ′(3)(ez), then |H3(1)| ≤1. For α = 1, Theorem 7 yields the following result:
COROLLARY 14. COROLLARY 14. If f ∈R(3)(ez), then |H3(1)| ≤1 16. CONCLUSION This paper is concerned with the upper bound of third Hankel determinant for a…
COROLLARY 14. If f ∈R(3)(ez), then |H3(1)| ≤1 16. CONCLUSION This paper is concerned with the upper bound of third Hankel determinant for a subclass of analytic functions, associated with exponential function. The results established here are very interesting and will motivate other researchers in this field to work on the similar classes by associating to other standard functions.
Function classes studied:

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