Abstract
In this paper we study sharp estimates of pre-Schwarzian derivatives of functions belonging to the Nehari-type classes by using techniques from differential equations. In the sequel, we also see that a solution of a complex differential equation has a special form in terms of ratio of hypergeometric functions resulting to an integral representation. Finally, we attempt to study those univalent functions in the unit disk for which the image domain is an unbounded John domain.
Results & Lemmas (11)
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Theorem 2.1.
Theorem 2.1. If f ∈N2(k), 0 ≤k ≤2, then (2) |Tf(z)| ≤2|z| −2β2Ak(|z|) 1 −|z|2,
Theorem 2.1. If f ∈N2(k), 0 ≤k ≤2, then (2) |Tf(z)| ≤2|z| −2β2Ak(|z|) 1 −|z|2 ,
Lemma 2.2.
Lemma 2.2. If f ∈M2(k), 0 ≤k ≤2, then |Tf(z)| ≤2|z| + √ 4 −2k 1 −|z|2. Equality holds at a single z ̸= 0 if and only if f is a suitable…
Lemma 2.2. If f ∈M2(k), 0 ≤k ≤2, then |Tf(z)| ≤2|z| + √ 4 −2k 1 −|z|2 . Equality holds at a single z ̸= 0 if and only if f is a suitable rotation of F0(z), where F0(z) = e √ 4 −2k tanh−1(z) −1 √ 4 −2k = 1 + z 1 −z
Corollary 2.3.
Corollary 2.3. [2, Lemma 1] If f ∈N2(2) then |Tf(z)| ≤ 2|z| 1 −|z|2. Equality holds at a single z ̸= 0 if and only if f is a rotation of 1…
Corollary 2.3. [2, Lemma 1] If f ∈N2(2) then |Tf(z)| ≤ 2|z| 1 −|z|2. Equality holds at a single z ̸= 0 if and only if f is a rotation of 1 2 ln 1 + z 1 −z. Similarly, the next result is stated as follows:
Theorem 2.4.
Theorem 2.4. If f ∈N0(k), 0 ≤k ≤π2/2, then |Tf(z)| ≤ √ 2k tan r k 2|z| !. Equality holds at a single z ̸= 0 if and only if f is a rotation…
Theorem 2.4. If f ∈N0(k), 0 ≤k ≤π2/2, then |Tf(z)| ≤ √ 2k tan r k 2|z| ! . Equality holds at a single z ̸= 0 if and only if f is a rotation of F1(z), where F1(z) = r 2 k tan r
Corollary 2.5.
Corollary 2.5. If f ∈N0(π2/2) then |Tf(z)| ≤π tan π 2 |z| . The equality holds at a single z ̸= 0 if and only if f is a rotation of 2 π…
Corollary 2.5. If f ∈N0(π2/2) then |Tf(z)| ≤π tan π 2 |z| . The equality holds at a single z ̸= 0 if and only if f is a rotation of 2 π tan π 2 z . Next we present a similar result for functions in the class N1(k). Since we use the same technique and it involves solution of a differential equation, as a supplementary result we
Theorem 2.6.
Theorem 2.6. A solution of the differential equation w′(z) = 1 2w2(z) + k 1 −z2, 0 ≤k ≤4,
Theorem 2.6. A solution of the differential equation w′(z) = 1 2w2(z) + k 1 −z2, 0 ≤k ≤4,
Theorem 2.7.
Theorem 2.7. If f ∈N1(k), 0 ≤k ≤4, then |Tf(z)| ≤k|z| F[(−1/4)(−3 + √ 1 + 2k), (1/4)(3 + √ 1 + 2k); 3/2; |z|2] F[(−1/4)(1 + √ 1 + 2k),…
Theorem 2.7. If f ∈N1(k), 0 ≤k ≤4, then |Tf(z)| ≤k|z| F[(−1/4)(−3 + √ 1 + 2k), (1/4)(3 + √ 1 + 2k); 3/2; |z|2] F[(−1/4)(1 + √ 1 + 2k), (1/4)(−1 + √ 1 + 2k); 1/2; |z|2] . Equality holds at a single z ̸= 0 if and only if f is a rotation of F2(z), where
Corollary 2.8.
Corollary 2.8. If f ∈N1(4) then |Tf(z)| ≤ 4|z| 1 −|z|2. Equality holds at a single z ̸= 0 if and only if f is a rotation of 1 4 2z 1 −z2…
Corollary 2.8. If f ∈N1(4) then |Tf(z)| ≤ 4|z| 1 −|z|2. Equality holds at a single z ̸= 0 if and only if f is a rotation of 1 4 2z 1 −z2 + ln 1 + z 1 −z . 3. Schwarzian derivative and John domains This section is devoted to the study of functions in Nehari-type classes. We begin with
Lemma 3.1.
Lemma 3.1. [3, Lemma 2] Let f be analytic and univalent in D. Then f(D) is a John domain if and only if there exists 0 < x < 1 such that…
Lemma 3.1. [3, Lemma 2] Let f be analytic and univalent in D. Then f(D) is a John domain if and only if there exists 0 < x < 1 such that sup |ζ|=1 sup r<1 (1 −ρ2)|f ′(ρζ)| (1 −r2)|f ′(rζ)| < 1, ρ = x + r 1 + xr. This characterization plays an important role to prove the following necessary condition for bounded John domains f(D), when f ∈N2(2) (see [3, Theorem 4]). In fact, in its proof, a relationship between the derivatives Sf and Tf as well as an upper bound for |Tf| are used.
Lemma 3.2.
Lemma 3.2. [3, Theorem 4] Let f ∈N2(2) and f(D) be a bounded John domain. Then lim sup |z|→1 (1 −|z|2)Re (zTf(z)) < 2. Naturally, one can…
Lemma 3.2. [3, Theorem 4] Let f ∈N2(2) and f(D) be a bounded John domain. Then lim sup |z|→1 (1 −|z|2)Re (zTf(z)) < 2. Naturally, one can ask the analog of Lemma 3.2 for the family N2(k), 0 ≤k < 2. From [2, Lemma 1] it is clear that for all bounded mappings, lim sup |z|→1 (1 −|z|2)2|Sf(z)| ≤k =⇒lim sup |z|→1 (1 −|z|2)|Tf(z)| ≤k. From this, we conclude that, for f ∈N2(k), 0 ≤k ≤2, lim sup |z|→1 (1 −|z|2)Re (zTf(z)) ≤k.
Theorem 3.3.
Theorem 3.3. Let f ∈M2(k), 0 ≤k < 2. Then lim sup |z|→1 (1 −|z|2)Re (zTf(z)) < 2 + √ 4 −2k.
Theorem 3.3. Let f ∈M2(k), 0 ≤k < 2. Then lim sup |z|→1 (1 −|z|2)Re (zTf(z)) < 2 + √ 4 −2k.
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