Abstract
Coefficient conjecture for K-quasiconformal harmonic mappings verified for starlike and close-to-convex functions. Sharp coefficient estimates for convex mappings established using subordination methods.
Results & Lemmas (8)
Each result is auto-extracted from the paper via OCR - the math is shown verbatim and may carry occasional transcription artifacts. Click to expand the full statement.
Theorem 1.1
Theorem 1.1. Let be any one of the three classes, and. Then Conjecture B holds with in place of. The constants A(n,k) and B(n,k) may be…
Theorem 1.1. Let $\mathcal{F}_0$ be any one of the three classes $\mathcal{S}_H^{*0}(K)$ , $\mathcal{K}_H^0(K)$ and $\mathcal{T}_H^0(K)$ . Then Conjecture B holds with $\mathcal{F}_0$ in place of $\mathcal{S}_H^0(K)$ .
The constants A(n,k) and B(n,k) may be simplified to the following forms
$$A(n,k) = \frac{1}{n(1-k)^3} \left( n^2 + (-2n^2 - 2n + 1)k + (n+1)^2 k^2 - k^{n+1} - k^{n+2} \right)$$
and
$$B(n,k) = \frac{k}{n(1-k)^3} \Big( (n-1)^2 + (-2n^2 + 2n + 1)k + n^2k^2 - k^n - k^{n+1} \Big),$$
respectively.
In order to show that A(n, k) and B(n, k) are increasing functions of k, we need the following lemma.
Lemma 1.1
Lemma 1.1. For and n > 2, let and for all, where Then and are strictly increasing on [0,1).
Lemma 1.1. For $x \in [0,1)$ and n > 2, let
$$\phi_n(x) = \frac{M_n(x)}{(1-x)^3}$$
and $\psi_n(x) = \frac{x}{(1-x)^3} M_{n-1}(x)$ for all $x \in [0,1)$ ,
where
$$(1.8) M_n(x) = n^2 + (-2n^2 - 2n + 1)x + (n+1)^2 x^2 - x^{n+1} - x^{n+2}.$$
Then $\phi_n$ and $\psi_n$ are strictly increasing on [0,1).
Corollary 1.1 · coeff
Corollary 1.1. Let be any one of the three classes, and. Then the coefficients of each function (K > 1) satisfy the sharp inequalities for,…
Corollary 1.1. Let $\mathcal{F}$ be any one of the three classes $\mathcal{S}_H^*(K)$ , $\mathcal{K}_H(K)$ and $\mathcal{T}_H(K)$ . Then the coefficients of each function $f \in \mathcal{F}$ (K > 1) satisfy the sharp inequalities
$$|a_n| \le E_n(k) := A(n, k_0) + \frac{1 - \sqrt{1 - k_0^2}}{k_0} B(n, k_0),$$
$$|b_n| \le F_n(k) := B(n, k_0) + \frac{1 - \sqrt{1 - k_0^2}}{k_0} A(n, k_0),$$
for $n=2,3,\ldots$ , where $k_0=\frac{2k}{1+k^2}$ , A(n,k) and B(n,k) are defined by (1.5) and (1.6), respectively. Equalities occur for the function $Q_k$ defined by
(1.10)
$$Q_k(z) = P_k(z) + \frac{\sqrt{K_0} - 1}{\sqrt{K_0} + 1} \overline{P_k(z)},$$
where $P_k(z) \in \mathcal{F}_0^0$ is defined by (1.4), $\mathcal{F}_0^0$ is any one of the three classes $\mathcal{S}_H^{*0}(K_0)$ , $\mathcal{K}_H^0(K_0)$ and $\mathcal{T}_H^0(K_0)$ and $K_0 = K^2$ .
The limiting case of Corollary 1.1 as $k \to 1^-$ gives the following well-known result.
Corollary 1.2 · coeff
Corollary 1.2. Let be any one of the three classes, and. Then the coefficients of each function satisfy the sharp inequalities and for
Corollary 1.2. Let $\mathcal{F}$ be any one of the three classes $\mathcal{S}_H^*$ , $\mathcal{K}_H$ and $\mathcal{T}_H$ . Then the coefficients of each function $f = h + \overline{g} \in \mathcal{F}$ satisfy the sharp inequalities
$$|a_n| < \frac{2n^2 + 1}{3}$$
and $|b_n| < \frac{2n^2 + 1}{3}$ for $n = 2, 3, \dots$
Theorem 1.2 · coeff
Theorem 1.2. The coefficients of each function satisfy the sharp inequalities where and. Specially, if n = 2, we have the sharp…
Theorem 1.2. The coefficients of each function $f \in \mathcal{C}^0_H(K)$ satisfy the sharp inequalities
$$|a_n| \le a(n,k), |b_n| \le b(n,k) \text{ and } |a_n| - |b_n| \le 1 \text{ for } n = 2,3,\ldots,$$
where
$$a(n,k) = \frac{n - k(n+1) + k^{n+1}}{n(1-k)^2}$$
and $b(n,k) = \frac{k}{n(1-k)^2}(n-1-nk+k^n)$ .
Specially, if n = 2, we have the sharp inequalities
$$|a_2| \le \frac{3K+1}{2K+2}$$
and $|b_2| \le \frac{K-1}{2K+2}$ .
Equalities occur for the function $P \in \mathcal{C}^0_H(K)$ defined by
$$(1.11) P(z) = h_k(z) + \overline{g_k(z)} = z + \sum_{n=2}^{\infty} a(n,k)z^n - \sum_{n=2}^{\infty} b(n,k)\overline{z}^n,$$
where
$$h_k(z) = \frac{z}{(1-k)(1-z)} - \frac{k}{(1-k)^2} \log\left(\frac{1-kz}{1-z}\right),$$
and
$$g_k(z) = \frac{-kz}{(1-k)(1-z)} - \frac{k}{(1-k)^2} \log\left(\frac{1-z}{1-kz}\right).$$
Theorem 1.2 leads also to sharp coefficient bounds for mappings of the class $\mathcal{C}_H(K)$ . In order to state this result, we need the following lemma.
Lemma 1.2
Lemma 1.2. For and, let and for all, where (1.12) Then and are strictly increasing on [0,1). Proof. Clearly, on [0, 1). Moreover,, and so…
Lemma 1.2. For $x \in [0,1)$ and $n \ge 2$ , let
$$G_n(x) = \frac{L_n(x)}{(1-x)^2}$$
and $H_n(x) = \frac{x}{(1-x)^2} L_{n-1}(x)$ for all $x \in [0, 1)$ ,
where
(1.12)
$$L_n(x) = n - (n+1)x + x^{n+1}$$
Then $G_n$ and $H_n$ are strictly increasing on [0,1).
Proof. Clearly, $L_n(x) = n(1-x) - x(1-x^n) = (1-x)[n-x(1+x+\cdots x^{n-1})] > 0$ on [0, 1). Moreover,
$L'_n(x) = -(n+1)(1-x^n)$ , $L''_n(x) = n(n+1)x^{n-1}$ and $L'''_n(x) = (n-1)n(n+1)x^{n-2}$ so that $L'_n(x) < 0$ on [0,1), $L''_n(x) > 0$ on (0,1), and $L'''_n(x) > 0$ on (0,1). Moreover, $L'_n(1) = 0$ and $L''_n(1) > 0$ . Now, a computation gives
$$G'_n(x) = \frac{F_n(x)}{(1-x)^3}$$
for all $x \in [0,1)$ ,
where $F_n(x) = (1 - x)L'_n(x) + 2L_n(x)$ . Again,
$$F'_n(x) = (1-x)L''_n(x) + L'_n(x)$$
and $F''_n(x) = (1-x)L'''_n(x)$ ,
showing that $F''_n(x) \ge 0$ for all $x \in [0,1)$ and $n \ge 2$ . Therefore, $F'_n(x) \le F'_n(1) = 0$ for all $x \in [0,1)$ , which in turn implies that $F_n(x) \ge F_n(1) = 0$ for all $x \in [0,1)$ , Thus, $G_n(x)$ is strictly increasing on (0,1).
For the proof the second part, we find that $H_2(x) = x$ and so, there is nothing to prove. We may thus, assume that $n \geq 3$ and we have
$$H'_n(x) = \frac{J_n(x)}{(1-x)^3}$$
for all $x \in [0,1)$ ,
where $J_n(x) = (1-x)[xL'_{n-1}(x) + L_{n-1}(x)] + 2xL_{n-1}(x)$ . We need to show that $J_n(x) \ge 0$ on [0,1). Indeed, $J_n(0) = n-1 > 0$ and we may rewrite $J_n(x)$ as
$$J_n(x) = x[(1-x)L'_{n-1}(x) + 2L_{n-1}(x)] + (1-x)L_{n-1}(x).$$
By the previous argument, it is clear that $J_n(x) > 0$ on (0,1) and for $n \ge 3$ . Thus, $H_n(x)$ is strictly increasing on (0,1).
Remark 1.3. First we observe that $nG_n(k) = a(n,k)$ and $nH_n(k) = b(n,k)$ . By Lemma 1.2, a(n,k) and b(n,k) are increasing functions of $k \in [0,1)$ . If $k \to 1^-$ , then
$$\lim_{k \to 1^{-}} a(n, k) = \frac{n+1}{2} \text{ and } \lim_{k \to 1^{-}} b(n, k) = \frac{n-1}{2}.$$
Hence, in this case, Theorem 1.2 coincides with the first part of Theorem C.
Corollary 1.3 · coeff
Corollary 1.3. The coefficients of each function (K > 1) satisfy the sharp inequalities and for n = 2, 3,..., where. Specially, if n = 2,…
Corollary 1.3. The coefficients of each function $f \in C_H(K)$ (K > 1) satisfy the sharp inequalities
$$|a_n| \le C_n(k) = a(n, k_0) + \left(\frac{1 - \sqrt{1 - k_0^2}}{k_0}\right) b(n, k_0)$$
and
$$|b_n| \le D_n(k) = b(n, k_0) + \left(\frac{1 - \sqrt{1 - k_0^2}}{k_0}\right) a(n, k_0)$$
for n = 2, 3, ..., where $k_0 = \frac{2k}{1+k^2}$ . Specially, if n = 2, we have the sharp inequalities
$$|a_2| \le C_2(k) = \frac{1+k+2k^2}{1+k^2} = \frac{2K^2-K+1}{K^2+1}$$
and
$$|b_2| \le D_2(k) = \frac{k(2+k+k^2)}{1+k^2} = \frac{(K-1)(2K^2+K+1)}{(K+1)(K^2+1)}.$$
Equalities occur for the function Q defined by
(1.13)
$$Q(z) = P(z) + \frac{\sqrt{K_0} - 1}{\sqrt{K_0} + 1} \overline{P(z)},$$
where $P(z) \in \mathcal{C}_H^0(K_0)$ is defined by (1.11) and $K_0 = K^2$ .
Remark 1.4. As before, we remark that $C_n(k)$ and $D_n(k)$ are strictly increasing functions of $k \in [0, 1)$ . If $k \to 1^-$ , then, as in the case of the proof of Corollary 1.2, we have
$$\lim_{k \to 1^{-}} C_n(k) = n$$
and $\lim_{k \to 1^{-}} D_n(k) = n$ .
Thus, in the limiting case, Corollary 1.3 coincides with the second part of Theorem C.
1.6. Typically real K-quasiconformal harmonic mappings. By (1.4), since $P_k(0) = 0$ , $h'(0) + \overline{g'(0)} = 1 > 0$ and $\frac{g'(z)}{h'(z)} = kz$ , we know that $P_k \in \mathcal{T}_H^0(K)$ (cf. [5] or [14, Theorem A]). We consider the coefficients estimate of $f \in \mathcal{T}_H(K)$ and $f \in \mathcal{T}_H^0(K)$ and show that Conjecture B holds for $\mathcal{T}_H^0(K)$ . More precisely, we have
Theorem 1.3 · coeff
Theorem 1.3. If, then, and we have the sharp inequalities stated in (1.7) hold. We present the proofs of Theorems 1.1, 1.2, and 1.3 in…
Theorem 1.3. If $f = h + \overline{g} \in \mathcal{T}_H^0(K)$ , then $a_1 = 1$ , and we have the sharp inequalities stated in (1.7) hold.
We present the proofs of Theorems 1.1, 1.2, and 1.3 in Section 2.
Function classes studied:
Coefficient bounds & claims (8)
Machine-extracted from the paper text - useful for cross-referencing, not a verified fact.
coefficient_bound
|a_n| ≤ A(n,k) = (n**2 + (-2*n**2-2*n+1)*k + (n+1)**2*k**2 - k**(n+1) - k**(n+2)) / (n*(1-k)**3) for class S^{*0}_H(K), K^0_H(K), T^0_H(K) (sharp) [Theorem 1.1]
coefficient_bound
|b_n| ≤ B(n,k) = k*((n-1)**2 + (-2*n**2+2*n+1)*k + n**2*k**2 - k**n - k**(n+1)) / (n*(1-k)**3) for class S^{*0}_H(K), K^0_H(K), T^0_H(K) (sharp) [Theorem 1.1]
coefficient_bound
|a_n| ≤ a(n,k) = (n - k*(n+1) + k**(n+1)) / (n*(1-k)**2) for class C^0_H(K) (sharp) [Theorem 1.2]
coefficient_bound
|a_2| ≤ (5*K+3)/(2*K+2) for class S^{*0}_H(K) (sharp) [Remark after Theorem 1.1]
coefficient_bound
|a_2| ≤ (3*K+1)/(2*K+2) for class C^0_H(K) (sharp) [Theorem 1.2]
function_family
Class S^{*0}_H(K): K-quasiconformal starlike harmonic mappings f=h+g in S^0_H with |g'/h'| <= k < 1, K=(1+k)/(1-k)
function_family
Class C^0_H(K): K-quasiconformal convex harmonic mappings f=h+g in C^0_H with |g'/h'| <= k < 1, K=(1+k)/(1-k)
function_family
Class T^0_H(K): K-quasiconformal typically real harmonic mappings with g'(0)=0 and |g'/h'| <= k
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