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Results & Lemmas (6)
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Theorem 2
Theorem 2. Let, and where is given by (2.1). Proof. Since it follows then that We recall the following result ([8]): If, then (3.3) If we…
Theorem 2. Let $\Delta \neq 0$ , and
$$\Delta_{p}\Psi_{q}\left[\begin{smallmatrix} (\lambda_{i}, & A_{i})_{1,p} & ; \\ (\mu_{i}, & B_{i})_{1,q} & ; \end{smallmatrix}\right] \in P(A,B) \text{ and } |z| \leq |B|, \text{ then}$$
$$\left| {}_{\mathcal{D}}\Psi_{q} \left[ \begin{matrix} (\lambda_{i} + A_{i}, A_{i})_{1,p} ; \\ (\mu_{i} + B_{i}, B_{i})_{1,q} ; \end{matrix} z \right] \right| \leq \frac{A - B}{\left| \Delta \right| (1 - |B| |z|^{2})} , \tag{3.1}$$
where $\Delta$ is given by (2.1).
Proof. Since
$$\Delta p \Psi_q \begin{bmatrix} (\lambda_i, A_i)_{1,p}; \\ (\mu_i, B_i)_{1,q}; \end{bmatrix} z$$
$$= 1 + \Delta \sum_{n=1}^{\infty} \left( \prod_{i=1}^{p} \Gamma \left( \lambda_{i} + A_{i} n \right) \right) \left( \prod_{i=1}^{q} \Gamma \left( \mu_{i} + B_{i} n \right) \right)^{-1} \frac{z^{n}}{n!} ,$$
it follows then that
$$\Delta \frac{d}{dz} p \Psi_q \begin{bmatrix} (\lambda_i, A_i)_{1,p}; \\ (\mu_i, B_i)_{1,q}; \end{bmatrix} = \Delta p \Psi_q \begin{bmatrix} (\lambda_i + A_i, A_i)_{1,p}; \\ (\mu_i + B_i, B_i)_{1,q}; \end{bmatrix} . \tag{3.2}$$
We recall the following result ([8]):
If
$$h(z) = 1 + \sum_{k=1}^{\infty} C_k z^k \in P(A,B), |z| < 1$$
, then
$$| h'(z) | \leq \begin{cases} \frac{A - B}{(1 - |B| |z|)^2} & |z| \leq |B|, \\ \frac{A - B}{(1 - |B|^2) (1 - |z|^2)} & |z| > |B|. \end{cases}$$
(3.3)
If we set
$$h(z) = \Delta p \Psi_q \begin{bmatrix} (\lambda_i, A_i)_{1,p}; \\ (\mu_i, B_i)_{1,q}; \end{bmatrix} \text{ in (3.3),}$$
and use (3.2) in the process, we are lead to the result (3.1).
Theorem 3
Theorem 3. Let, and then for and |z| < 1: and Proof. Using (1.1) and (1.4), we find that (3.6) Then (3.7) in (2.8) and (2.9), and using…
Theorem 3. Let $\Delta \neq 0$ , and
$$\Delta z_{p}\Psi_{q}\left[ (\lambda_{i}, A_{i})_{1,p}; \atop (\mu_{i}, B_{i})_{1,q}; z \right] \in R (A,B),$$
then for $Re(\gamma) > 0$ and |z| < 1:
$$\left| p+2\Psi_{q+2} \left[ \begin{array}{cccc} (\lambda_{i}, A_{i})_{1,p}, (2,1), (\gamma+1,1) & ; \\ (\mu_{i}, B_{i})_{1,q}, (1,1), (\gamma+\alpha+1,1) & ; \end{array} \right] \right|$$
$$\leq \left[\Delta \Gamma \left(\alpha + 1\right) \begin{pmatrix} \alpha + \gamma \\ \gamma \end{pmatrix}\right]^{-1} \left(\frac{1 + A |z|}{1 + B |z|}\right), \tag{3.4}$$
and
$$Re\left\{ p+2\Psi_{q+2} \left[ \begin{array}{cc} (\lambda_{i}, A_{i})_{1,p}, (2,1), (\gamma+1,1); \\ (\mu_{i}, B_{i})_{1,q}, (1,1), (\gamma+\alpha+1,1); \end{array} z \right] \right\}$$
$$\geq \left[ \Delta \Gamma \left( \alpha + 1 \right) \begin{pmatrix} \alpha + \gamma \\ \gamma \end{pmatrix} \right]^{-1} \left( \frac{1 - A |z|}{1 - B |z|} \right) . \tag{3.5}$$
Proof. Using (1.1) and (1.4), we find that
$$\phi_{\gamma}^{\alpha} \left\{ \Delta z_{p} \Psi_{q} \left[ \begin{pmatrix} \lambda_{i}, A_{i} \end{pmatrix}_{1,p}; \\ (\mu_{i}, B_{i})_{1,q}; z \right] \right\}$$
$$= z + \Delta \Gamma(\alpha+1) {\alpha+\gamma \choose \gamma} \sum_{n=1}^{\infty} \frac{\prod_{i=1}^{p} \Gamma(\lambda_i + A_i n) \Gamma(\gamma+1+n)}{\prod_{i=1}^{q} \Gamma(\mu_i + B_i n) \Gamma(\gamma+\alpha+1+n)} \frac{z^{n+1}}{n!}.$$
(3.6)
Then
$$\frac{d}{dz} \left\{ \varphi_{\gamma}^{\alpha} \left( \Delta z_{p} \Psi_{q} \left[ \begin{pmatrix} \lambda_{i}, A_{i} \end{pmatrix}_{1,p}; \\ (\mu_{i}, B_{i})_{1,q}; z \right] \right) \right\}$$
$$= \Delta\Gamma(\alpha+1) {\alpha+\gamma \choose \gamma} {\Psi_{q+2}} {\{(\lambda_i, A_i)_{1,p}, (2,1), (\gamma+1,1); z\} \atop (\mu_i, B_i)_{1,q}, (1,1), (\gamma+\alpha+1,1); z\}}.$$
$$\text{Taking } G(z) = \phi_{\gamma}^{\alpha} \left( \Delta z {}_{p} \Psi_{q} {\{(\lambda_i, A_i)_{1,p}; z\} \atop (\mu_i, B_i)_{1,q}; z\}} \right)$$
(3.7)
in (2.8) and (2.9), and using (3.7), we obtain the inequalities (3.4) and (3.5), respectively.
Corollary 1
Corollary 1. L~r Fd + v) jy (z) c P *(a), ~/: (i) (4.4) (ii), (4.5) (iii) (4.6) (iv) (v)
Corollary 1. L~r Fd + v) jy (z) c P\*(a), ~/:
(i)
$$\left|\frac{1}{\Gamma(1+\nu+\mu n)}\right| \leq \frac{2(1-\alpha)n!}{\left|\Gamma(1+\nu)\right|},$$
(4.4)
(ii)
$$|J_{\nu}^{\mu}(z)| \leq \frac{1}{|\Gamma(1+\nu)|} \left( \frac{1+(1-2\alpha)|z|}{1-|z|} \right)$$
, (4.5)
(iii)
$$\operatorname{Re}\left\{J_{\nu}^{\mu}\left(z\right)\right\} \geq \frac{1}{\Gamma\left(1+\nu\right)}\left(\frac{1-\left(1-2\alpha\right)\left|z\right|}{1+\left|z\right|}\right),$$
(4.6)
(iv)
$$\left| {}_{1}\Psi_{2} \right|^{(1, 1)} ; z \left| {}_{(1+\nu, \mu), (2, 1);} \right|$$
$$\geq \frac{(2\alpha-1)}{|\Gamma(1+\nu)|} \left[ 1 + \frac{2(1-\alpha)}{1-2\alpha} \cdot \frac{\log(1-|z|)}{|z|} \right], \tag{4.7}$$
(v)
$$\left| \Psi_{2} \begin{bmatrix} (1, 1) \\ (1+\nu, \mu), (2, 1) \end{bmatrix} \right|$$
$$\geq \frac{(2\alpha-1)}{|\Gamma(1+\nu)|} \left[ 1 - \frac{2(1-\alpha)}{1-2\alpha} \cdot \frac{\log(1+|z|)}{|z|} \right], \tag{4.8}$$
Corollary 2
Corollary 2. If r i + v >Jf z >e P * a >,and ) z ] S I,then (4.9)
Corollary 2. If r i + v >Jf z >e P \* a > ,and ) z ] S I ,then
$$\left| J_{1+\nu+\mu}^{\mu} \left( z \right) \right| \leq \frac{2\left( 1-\alpha \right)}{\left| \Gamma\left( 1+\nu \right) \right| \left( 1+\left| z \right|^{2} \right)} .$$
(4.9)
Corollary 3
Corollary 3. Let r (03B2) > z i " # > /« E03B1, 03B2 z ) e P * a ),, then (i), (4.10) (ii), (4.11) (iii) (4.12) (iv) (v)
Corollary 3. Let r (03B2) > z i " # > /« E03B1, 03B2 z ) e P\* a ), , then
(i)
$$\left|\frac{1}{\Gamma(\beta + \alpha n)}\right| \le \frac{2(1-\alpha)n!}{|\Gamma(\beta)|}$$
, (4.10)
(ii)
$$|z^{(1-\beta)/\alpha} E_{\alpha,\beta}(z)| \le \frac{1}{|\Gamma(\beta)|} \left( \frac{1 + (1-2\alpha)|z|}{1 + |z|} \right)$$
, (4.11)
(iii)
$$Re\{z^{(1-\beta)/\alpha} E_{\alpha,\beta}(z)\} \ge \frac{1}{|\Gamma(\beta)|} \left(\frac{1-(1-2\alpha)|z|}{1+|z|}\right),$$
(4.12)
(iv)
$$\left| {}_{2}\Psi_{2} \left[ {}_{(\beta,\alpha)}^{(1,1)}, {}_{(2,1)}^{(1,1)}; z \right] \right|$$
$$\leq \frac{(2 \alpha - 1)}{|\Gamma(\beta)|} \left[ 1 + \frac{2(1 - \alpha)}{1 - 2 \alpha} \cdot \frac{\log(1 - |z|)}{|z|} \right] \tag{4.13}$$
(v)
$$\left[ 2\Psi_{2} \left[ \begin{pmatrix} 1,1 \\ \beta,\alpha \end{pmatrix}, \begin{pmatrix} 1,1 \\ 2,1 \end{pmatrix}; z \right] \right]$$
$$\geq \frac{(2\alpha - 1)}{|\Gamma(\beta)|} \left[ 1 - \frac{2(1-\alpha)}{1-2\alpha} \cdot \frac{\log(1+|z|)}{|z|} \right], \tag{4.14}$$
Corollary 4
Corollary 4. If 0393 (03B2) z(1-03B2)/03B1 E03B1,03B2 (z> e P * «), and ] z ] I, then
Corollary 4. If 0393 (03B2) z(1-03B2)/03B1 E03B1,03B2 (z> e P\* «) , and ] z ] I, then
$$\left| \mathbf{1} \Psi_{1} \left[ \begin{pmatrix} (2,1) \\ (\beta+\alpha,\alpha) \end{pmatrix}^{\prime}, z \right] \right| \leq \frac{2 (1-\alpha)}{\left| \Gamma(\beta) \right| (1+|z|^{2})}.$$